Invert Binary Tree

Invert a binary tree.

Example

Input:

     4
   /   \
  2     7
 / \   / \
1   3 6   9

Output:

     4
   /   \
  7     2
 / \   / \
9   6 3   1

Note

Code

public class Solution {
    /**
     * @param root: a TreeNode, the root of the binary tree
     * @return: nothing
     */
    public void invertBinaryTree(TreeNode root) {
        if (root == null) {
            return;
        }
        TreeNode temp = root.left;
        root.left = root.right;
        root.right = temp;

        invertBinaryTree(root.left);
        invertBinaryTree(root.right);
    }
}

public class Solution {
    /**
     * @param root: a TreeNode, the root of the binary tree
     * @return: nothing
     */
    public void invertBinaryTree(TreeNode root) {
        // write your code here
        if (root == null)
        {
            return;
        }

        Stack<TreeNode> stack = new Stack<>();
        stack.push(root);
        while(!stack.isEmpty())
        {
            TreeNode node = stack.pop();

            TreeNode t = node.left;
            node.left = node.right;
            node.right = t;

            if(node.left != null)
            {
                stack.push(node.left);
            }
            if(node.right != null)
            {
                stack.push(node.right);
            }
        }

    }
}