Given an arrayAof positive integers, call a (contiguous, not necessarily distinct) subarray ofA_good_if the number of different integers in that subarray is exactlyK.
Input:
A = [1,2,1,2,3], K = 2
Output:
7
Explanation:
Subarrays formed with exactly 2 different integers: [1,2], [2,1], [1,2], [2,3], [1,2,1], [2,1,2], [1,2,1,2].
Example 2:
Input:
A = [1,2,1,3,4], K = 3
Output: 3
Explanation:
Subarrays formed with exactly 3 different integers: [1,2,1,3], [2,1,3], [1,3,4].
Note
关键是求刚好K个不同的,参考之前的最多k个不同
numAtMostK(nums, k) - numAtMostK(nums, k - 1);
子串最多有k个不同的,满足条件的最大长度的窗口长度为就为个数
Code
class Solution {
public int subarraysWithKDistinct(int[] nums, int k) {
return numAtMostK(nums, k) - numAtMostK(nums, k - 1);
}
private int numAtMostK(int[] nums, int k) {
Map<Integer, Integer> map = new HashMap<>();
int j = 0;
int len = nums.length;
int count = 0;
int res = 0;
for (int i = 0; i < len; i++) {
while (j < len && count <= k) {
map.put(nums[j], map.getOrDefault(nums[j], 0) + 1);
if (map.get(nums[j]) == 1) {
if (count == k) {
map.put(nums[j], map.get(nums[j]) - 1);
break;
}
count++;
}
j++;
}
res += j - i;
if (map.getOrDefault(nums[i], 0) == 1) {
count--;
}
map.put(nums[i], map.get(nums[i]) - 1);
}
return res;
}
}